Day 1: Historian Hysteria

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FAQ

  • proved_unglue@programming.dev
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    6 months ago

    Kotlin

    No 💜 for Kotlin here?

    import kotlin.math.abs
    
    fun part1(input: String): Int {
        val diffs: MutableList<Int> = mutableListOf()
        val pair = parse(input)
        pair.first.sort()
        pair.second.sort()
        pair.first.forEachIndexed { idx, num ->
            diffs.add(abs(num - pair.second[idx]))
        }
        return diffs.sum()
    }
    
    fun part2(input: String): Int {
        val pair = parse(input)
        val frequencies = pair.second.groupingBy { it }.eachCount()
        var score = 0
        pair.first.forEach { num ->
            score += num * frequencies.getOrDefault(num, 0)
        }
        return score
    }
    
    private fun parse(input: String): Pair<MutableList<Int>, MutableList<Int>> {
        val left: MutableList<Int> = mutableListOf()
        val right: MutableList<Int> = mutableListOf()
        input.lines().forEach { line ->
            if (line.isNotBlank()) {
                val parts = line.split("\\s+".toRegex())
                left.add(parts[0].toInt())
                right.add(parts[1].toInt())
            }
        }
        return left to right
    }
    
    • the_beber@lemm.ee
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      6 months ago

      I have another Kotlin (albeit similar) solution:

      import kotlin.math.abs
      
      fun main() {
      
          fun getLists(input: List<String>): Pair<List<Int>, List<Int>> {
              val unsortedPairs = input.map {
                  it.split("   ").map { it.toInt() }
              }
      
              val listA = unsortedPairs.map { it.first() }
              val listB = unsortedPairs.map { it.last() }
              return Pair(listA, listB)
          }
      
          fun part1(input: List<String>): Int {
              val (listA, listB) = getLists(input)
      
              return listA.sorted().zip(listB.sorted()).sumOf { abs(it.first - it.second) }
          }
      
          fun part2(input: List<String>): Int {
              val (listA, listB) = getLists(input)
      
              return listA.sumOf { number ->
                  number * listB.count { it == number }
              }
          }
      
          // Or read a large test input from the `src/Day01_test.txt` file:
          val testInput = readInput("Day01_test")
          check(part1(testInput) == 11)
          check(part2(testInput) == 31)
      
          // Read the input from the `src/Day01.txt` file.
          val input = readInput("Day01")
          part1(input).println()
          part2(input).println()
      }
      
      

      It’s a bit more compact. (If you take out the part that actually calls the functions on the (test-)input.)

      • proved_unglue@programming.dev
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        6 months ago

        Thanks! I like the Pair destruction and zip().sumOf() approach. I’m relatively new to Kotlin, so this is a good learning experience. 😅

  • rwdf@lemmy.world
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    6 months ago

    Go

    package main
    
    import (
    	"bufio"
    	"fmt"
    	"os"
    	"sort"
    	"strconv"
    	"strings"
    )
    
    func main() {
    	input, _ := os.Open("input.txt")
    	defer input.Close()
    
    	left, right := []int{}, []int{}
    
    	scanner := bufio.NewScanner(input)
    	for scanner.Scan() {
    		line := scanner.Text()
    		splitline := strings.Split(line, "   ")
    		l, _ := strconv.Atoi(splitline[0])
    		r, _ := strconv.Atoi(splitline[1])
    		left, right = append(left, l), append(right, r)
    	}
    
    	fmt.Printf("part 1 - total diff: %d\n", part1(left, right))
    	fmt.Printf("part 2 - new total: %d\n", part2(left, right))
    }
    
    func part1(left, right []int) int {
    	diff := 0
    	sort.Ints(left)
    	sort.Ints(right)
    
    	for i, l := range left {
    		if l > right[i] {
    			diff += (l - right[i])
    		} else {
    			diff += (right[i] - l)
    		}
    	}
    	return diff
    }
    
    func part2(left, right []int) int {
    	newTotal := 0
    
    	for _, l := range left {
    		matches := 0
    		for _, r := range right {
    			if l == r {
    				matches++
    			}
    		}
    		newTotal += l * matches
    	}
    	return newTotal
    }
    
  • sjmulder@lemmy.sdf.org
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    6 months ago

    JavaScript

    After writing a procedural to-the-point version in C, tried a JavaScript solution too because it’s just perfect for list comprehension. The part 2 search is inefficient but the data size is small.

    Code
    const fs = require("fs");
    const U = require("./util");
    
    const pairs = fs
        .readFileSync(process.argv[2] || process.stdin.fd, "utf8")
        .split("\n")
        .filter(x => x != "")
        .map(x => x.split(/ +/).map(Number));
    
    const ls = pairs.map(x => x[0]); ls.sort();
    const rs = pairs.map(x => x[1]); rs.sort();
    
    const p1 = U.sum(ls.map((l, i) => Math.abs(l - rs[i])));
    const p2 = U.sum(ls.map(l => l * U.count(rs, l)));
    
    console.log("01:", p1, p2);
    

    https://github.com/sjmulder/aoc/blob/master/2024/js/day01.js

  • SteveDinn@lemmy.ca
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    6 months ago

    C#

    using System;
    using System.Linq;
    
    public record Point(int X, int Y); 
    
    static class Program
    {
        static async Task Main(string[] args)
        {
            var data = (await ReadInputFromFile("data.txt")).ToArray();
    
            var part1Answer = CalculateTotalDifference(data);
            Console.WriteLine($"Part 1 = {part1Answer}");
    
            var part2Answer = CountFrequencies(data);
            Console.WriteLine($"Part 2 = {part2Answer}");
        }
    
        public static int CountFrequencies(ICollection<Point> points)
        {
            var freq = points
                .GroupBy(p => p.Y)
                .ToDictionary(g => g.Key, g => g.Count());
            return points
                .Sum(p => freq.GetValueOrDefault(p.X, 0) * p.X);
        }
    
        public static int CalculateTotalDifference(ICollection<Point> points)
            => points.OrderBy(p => p.X)
                .Zip(
                    points.OrderBy(p => p.Y),
                    (px, py) => Math.Abs(px.X - py.Y))
                .Sum();
    
        public static readonly char[] Delimiter = new char[] { ' ' };
        public static async Task<IEnumerable<Point>> ReadInputFromFile(string path)
            => (await File.ReadAllLinesAsync(path))
                .Select(l =>
                {
                    var parts = l.Split(
                        Delimiter,
                        StringSplitOptions.TrimEntries | StringSplitOptions.RemoveEmptyEntries);
                    return new Point(int.Parse(parts[0]), int.Parse(parts[1]));
                });
    }
    
  • Andy@programming.dev
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    6 months ago

    Factor

    : get-input ( -- left-list right-list )
      "vocab:aoc-2024/01/input.txt" utf8 file-lines
      [ split-words harvest ] map unzip
      [ [ string>number ] map ] bi@ ;
    
    : part1 ( -- n )
      get-input
      [ sort ] bi@
      [ - abs ] 2map-sum ;
    
    : part2 ( -- n )
      get-input
      histogram
      '[ dup _ at 0 or * ] map-sum ;
    

    https://github.com/AndydeCleyre/aoc-2024

  • rwdf@lemmy.world
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    6 months ago

    Elixir

    Total noob, but it’s fun to learn.

    {left, right} =
      File.read!("./input.txt")
      |> String.split("\n", trim: true)
      |> Enum.map(fn line ->
        String.split(line)
        |> Enum.map(&String.to_integer/1)
        |> List.to_tuple()
      end)
      |> Enum.unzip()
      |> then(fn {left, right} ->
        {Enum.sort(left), Enum.sort(right)}
      end)
    
    diffs =
      Enum.zip(left, right)
      |> Enum.map(fn {l, r} -> abs(l - r) end)
      |> Enum.sum()
    
    freqs =
      Enum.filter(right, fn r -> r in left end)
      |> Enum.frequencies()
    
    freqsum =
      Enum.map(left, fn n ->
        freq = Map.get(freqs, n, 0)
        n * freq
      end)
      |> Enum.sum()
    
    IO.puts("part 1: #{diffs}")
    IO.puts("part 2: #{freqsum}")
    
    
  • hosaka@programming.dev
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    6 months ago

    Zig

    const std = @import("std");
    const List = std.ArrayList;
    const Map = std.AutoHashMap;
    
    const splitSeq = std.mem.splitSequence;
    const splitScalar = std.mem.splitScalar;
    const parseInt = std.fmt.parseInt;
    const print = std.debug.print;
    const sort = std.sort.block;
    
    var gpa = std.heap.GeneralPurposeAllocator(.{}){};
    const alloc = gpa.allocator();
    
    const Answer = struct {
        distance: u32,
        similarity: u32,
    };
    
    fn lessThan(_: void, lhs: []const u8, rhs: []const u8) bool {
        return std.mem.lessThan(u8, lhs, rhs);
    }
    
    pub fn solve(input: []const u8) !Answer {
        var rows = splitScalar(u8, input, '\n');
        var left_list = List([]const u8).init(alloc);
        defer left_list.deinit();
        var right_list = List([]const u8).init(alloc);
        defer right_list.deinit();
    
        // PART 1
    
        // split the rows into two lists
        while (rows.next()) |row| {
            var sides = splitSeq(u8, row, "   ");
            try left_list.append(sides.next() orelse break);
            try right_list.append(sides.next() orelse break);
        }
        _ = left_list.pop(); // last null
    
        // sort both lists
        sort([]const u8, left_list.items, {}, lessThan);
        sort([]const u8, right_list.items, {}, lessThan);
    
        var distance: u32 = 0;
        for (left_list.items, right_list.items) |left, right| {
            distance += @abs(try parseInt(i32, left, 10) - try parseInt(i32, right, 10));
        }
    
        // PART 2
        var right_scores = Map(i32, u32).init(alloc);
        defer right_scores.deinit();
    
        // count number of item appearances in the right list
        for (right_list.items) |item| {
            const value = try parseInt(i32, item, 10);
            const result = try right_scores.getOrPut(value);
            if (!result.found_existing) {
                result.value_ptr.* = 1;
            } else {
                result.value_ptr.* += 1;
            }
        }
    
        // sum up similarity between items in left list and right list scores
        var similarity: u32 = 0;
        for (left_list.items) |item| {
            const value = try parseInt(i32, item, 10);
            const result = right_scores.get(value) orelse 0;
            similarity += @as(u32, @intCast(value)) * result;
        }
        return Answer{ .distance = distance, .similarity = similarity };
    }
    
    pub fn main() !void {
        const answer = try solve(@embedFile("input.txt"));
        print("Part 1: {d}\n", .{answer.distance});
        print("Part 2: {d}\n", .{answer.similarity});
    }
    
    test "test input" {
        const answer = try solve(@embedFile("test.txt"));
        try std.testing.expectEqual(answer.distance, 11);
        try std.testing.expectEqual(answer.similarity, 31);
    }
    
    
  • Amy@lemmy.sdf.org
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    6 months ago

    Haskell

    Plenty of scope for making part 2 faster, but I think simple is best here. Forgot to sort the lists in the first part, which pushed me waaay off the leaderboard.

    import Data.List
    
    main = do
      [as, bs] <- transpose . map (map read . words) . lines <$> readFile "input01"
      print . sum $ map abs $ zipWith (-) (sort as) (sort bs)
      print . sum $ map (\a -> a * length (filter (== a) bs)) as
    
  • Rin@lemm.ee
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    6 months ago

    TypeScript

    Solution
    import { AdventOfCodeSolutionFunction } from "./solutions";
    
    function InstancesOf(sorted_array: Array<number>, value: number) {
        const index = sorted_array.indexOf(value);
        if(index == -1)
            return 0;
    
        let sum = 1;
    
        for (let array_index = index + 1; array_index < sorted_array.length; array_index++) {
            if(sorted_array[array_index] != value)
                break;
    
            sum += 1;
        }
    
        return sum;
    }
    
    export const solution_1: AdventOfCodeSolutionFunction = (input) => {
        const left: Array<number> = [];
        const right: Array<number> = [];
    
        const lines = input.split("\n");
    
        for (let index = 0; index < lines.length; index++) {
            const element = lines[index].trim();
            if(!element)
                continue;
    
            const leftRight = element.split("   ");
            left.push(Number(leftRight[0]));
            right.push(Number(leftRight[1]));
        }
    
        const numSort = (a: number, b: number) => a - b;
        left.sort(numSort);
        right.sort(numSort);
    
        let sum = 0;
        for (let index = 0; index < left.length; index++) {
            const leftValue = left[index];
            const rightValue = right[index];
    
            sum += Math.abs(leftValue - rightValue);
        }
    
        const part1 = `Part 1: ${sum}`;
    
        sum = 0;
        for (let index = 0; index < left.length; index++) {
            sum += left[index] * InstancesOf(right, left[index]);
        }
    
        const part2 = `Part 2: ${sum}`;
    
        return `${part1}\n${part2}`;
    };
    

    Not the most elegant solution but it works. Decided to reuse the array since it is sorted for both sides.

  • vole@lemmy.world
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    6 months ago

    Raku

    I’m trying warm up to Raku again.

    Solution

    github

    use v6;
    
    sub MAIN($input) {
        my $file = open $input;
    
        grammar LocationList {
            token TOP { <row>+%"\n" "\n"* }
            token row { <left=.id> " "+ <right=.id> }
            token id { \d+ }
        }
    
        my $locations = LocationList.parse($file.slurp);
        my @rows = $locations<row>.map({ (.<left>.Int, .<right>.Int)});
        my $part-one-solution = (@rows[*;0].sort Z- @rows[*;1].sort)».abs.sum;
        say "part 1: $part-one-solution";
    
        my $rbag = bag(@rows[*;1].sort);
        my $part-two-solution = @rows[*;0].map({ $_ * $rbag{$_}}).sum;
        say "part 2: $part-two-solution";
    }
    

    I’m happy to see that Lemmy no longer eats Raku code.

  • Quant@programming.dev
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    6 months ago

    Uiua

    Decided to try and use Uiua for each day this year. At least I’m not the only one to get this idea ^^

    Run with example input here

    PartOne ← (
      &rs ∞ &fo "input-1.txt"
      ⊜(⊜⋕≠@ .)≠@\n.
      ≡⍆⍉
      ⌵/-
      /+
    )
    
    PartTwo ← (
      &rs ∞ &fo "input-1.txt"
      ⊜(⊜⋕≠@ .)≠@\n.
      ⊢⟜⊣⍉
      0
      ⍢(+⊙(:⊙(×⧻⊚◡⌕)↘1⟜⊢)|⋅(≠0⧻))
      ⊙(◌◌) # just cleaning up the stack
    )
    
    &p "Day 1:"
    &pf "Part 1: "
    &p PartOne
    &pf "Part 2: "
    &p PartTwo
    
    
  • aurele@sh.itjust.works
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    6 months ago

    Elixir

    defmodule AdventOfCode.Solution.Year2024.Day01 do
      use AdventOfCode.Solution.SharedParse
    
      @impl true
      def parse(input) do
        numbers =
          input
          |> String.split("\n", trim: true)
          |> Enum.map(fn l -> String.split(l, ~r/\s+/) |> Enum.map(&String.to_integer/1) end)
    
        {Stream.map(numbers, &Enum.at(&1, 0)), Stream.map(numbers, &Enum.at(&1, 1))}
      end
    
      def part1({left, right}) do
        Enum.zip_reduce(Enum.sort(left), Enum.sort(right), 0, &(&3 + abs(&1 - &2)))
      end
    
      def part2({left, right}) do
        freq = Enum.frequencies(right)
        left |> Stream.map(&(&1 * Map.get(freq, &1, 0))) |> Enum.sum()
      end
    end